977. Squares of a Sorted Array
Easy
Given an integer array
nums sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.Example 1:
Input: nums = [-4,-1,0,3,10]
Output:
[0,1,9,16,100]
Explanation:
After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].
Example 2:
Input: nums = [-7,-3,2,3,11]
Output:
[4,9,9,49,121]
Constraints:
1 <= nums.length <= 104-104 <= nums[i] <= 104numsis sorted in non-decreasing order.
Follow up: Squaring each element and sorting the new array is very trivial, could you find an
O(n) solution using a different approach?
暴力解(超級慢！)，先平方再sort。
func sortedSquares(nums []int) []int {
for i:=0; i<len(nums); i++ {
nums[i] = nums[i]*nums[i]
}
sort.Ints(nums)
return nums
}
改良後的方法，log(n)。
因為input 的數列已經依照大小排列好，所以使用兩個指針，一個指向頭，一個指向尾，來比較其絕對值大小，將較大的數字放進答案陣列中後移動指針。
Runtime: 19 ms, faster than 99.75%
Memory Usage: 6.6 MB, less than 95.67%
func sortedSquares(nums []int) []int {
l := 0
r := len(nums)-1
length := len(nums)
index := length-1
ans := make([]int, length)
for l <= r {
if Abs(nums[l])>Abs(nums[r]) {
ans[index] = nums[l]*nums[l]
l++
} else {
ans[index] = nums[r]*nums[r]
r--
}
index--
}
return ans
}
func Abs(x int) int {
if x < 0 {
return -x
}
return x
}