905. Sort Array By Parity

Easy

Given an integer array nums, move all the even integers at the beginning of the array followed by all the odd integers.

Return any array that satisfies this condition.

Example 1:

Input: nums = [3,1,2,4]
Output: [2,4,3,1]
Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

Example 2:

Input: nums = [0]
Output: [0]

Constraints:

  • 1 <= nums.length <= 5000

  • 0 <= nums[i] <= 5000

解題

func sortArrayByParity(nums []int) []int {
    sort.Slice(nums, func(i, j int) bool {
        if nums[i] % 2 == 0 && nums[j] % 2 == 1 {
            return true
        }
        if nums[i] % 2 == 1 && nums[j] % 2 == 0 {
            return false
        }

        return nums[i] < nums[j]
    })

    return nums
}

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