1941. Check if All Characters Have Equal Number of Occurrences

Easy
​
Given a string s, return true if s is a good string, or false otherwise.
A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).
Example 1:
Input: s = "abacbc"
Output:
true
Explanation:
The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.
Example 2:
Input: s = "aaabb"
Output:
false
Explanation:
The characters that appear in s are 'a' and 'b'.
'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.
Constraints:
  • 1 <= s.length <= 1000
  • s consists of lowercase English letters.

解題

Runtime: 5 ms, faster than 35.29%
Memory Usage: 2.1 MB, less than 82.35%
func areOccurrencesEqual(s string) bool {
count := make([]int, 26)
for i:=0; i<len(s); i++ {
count[s[i]-'a']++
}
for i:=1; i<len(s); i++ {
if count[s[i]-'a'] != count[s[i-1]-'a'] { return false }
}
return true
}