1941. Check if All Characters Have Equal Number of Occurrences

Easy

Given a string s, return true if s is a good string, or false otherwise.

A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).

Example 1:

Input: s = "abacbc"
Output:
 true
Explanation:
 The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.

Example 2:

Input: s = "aaabb"
Output:
 false
Explanation:
 The characters that appear in s are 'a' and 'b'.
'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.

Constraints:

• 1 <= s.length <= 1000

• s consists of lowercase English letters.

解題

Runtime: 5 ms, faster than 35.29%

Memory Usage: 2.1 MB, less than 82.35%

func areOccurrencesEqual(s string) bool {
    count := make([]int, 26)
    
    for i:=0; i<len(s); i++ {
        count[s[i]-'a']++
    }
    
    for i:=1; i<len(s); i++ {
        if count[s[i]-'a'] != count[s[i-1]-'a'] { return false }
    }
    
    
    return true
}