2278. Percentage of Letter in String

Easy
​
Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.
Example 1:
Input: s = "foobar", letter = "o"
Output:
33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = "jjjj", letter = "k"
Output:
0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.
Constraints:
  • 1 <= s.length <= 100
  • s consists of lowercase English letters.
  • letter is a lowercase English letter.

解題

這題如果用 float32 , 會在一題測資出錯。
Runtime: 0 ms, faster than 100.00%
Memory Usage: 2 MB, less than 61.82%
func percentageLetter(s string, letter byte) int {
count := 0
for i:=0; i<len(s); i++ {
if s[i] == letter { count++ }
}
return int((float64(count) / float64(len(s))) * 100)
}