1122. Relative Sort Array
Easy
Given two arrays
arr1 and arr2, the elements of arr2 are distinct, and all elements in arr2 are also in arr1.Sort the elements of
arr1 such that the relative ordering of items in arr1 are the same as in arr2. Elements that do not appear in arr2 should be placed at the end of arr1 in ascending order.Example 1:
Input: arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6]
Output:
[2,2,2,1,4,3,3,9,6,7,19]
Example 2:
Input: arr1 = [28,6,22,8,44,17], arr2 = [22,28,8,6]
Output:
[22,28,8,6,17,44]
Constraints:
1 <= arr1.length, arr2.length <= 10000 <= arr1[i], arr2[i] <= 1000- All the elements of
arr2are distinct. - Each
arr2[i]is inarr1.
func relativeSortArray(arr1 []int, arr2 []int) []int {
m := make(map[int]int)
for i, val := range arr2 {
m[val] = i
}
for _, val := range arr1 {
if _, ok := m[val]; !ok {
m[val] = 1024
}
}
sort.Slice(arr1, func(i, j int) bool {
if m[arr1[i]]==m[arr1[j]] { return arr1[i]<arr1[j] }
return m[arr1[i]]<m[arr1[j]]
})
return arr1
}