1496. Path Crossing
Easy
Given a string
path, where path[i] = 'N', 'S', 'E' or 'W', each representing moving one unit north, south, east, or west, respectively. You start at the origin (0, 0) on a 2D plane and walk on the path specified by path.Return
true if the path crosses itself at any point, that is, if at any time you are on a location you have previously visited. Return false otherwise.Example 1:
Input: path = "NES"
Output:
false
Explanation:
Notice that the path doesn't cross any point more than once.
Example 2:
Input: path = "NESWW"
Output:
true
Explanation:
Notice that the path visits the origin twice.
Constraints:
1 <= path.length <= 104path[i]is either'N','S','E', or'W'.
Runtime: 0 ms, faster than 100.00%
Memory Usage: 2.2 MB, less than 26.09%
func isPathCrossing(path string) bool {
visited := make(map[[2]int]bool)
visited[[2]int{ 0, 0 }] = true
x, y := 0, 0
for _, char := range path {
if char== 'N' {
y++
} else if char=='E' {
x++
} else if char=='S' {
y--
} else {
x--
}
if _, ok := visited[[2]int{x, y}]; ok {
return true
} else {
visited[[2]int{x, y}] = true
}
}
return false
}