# 1450. Number of Students Doing Homework at a Given Time

Easy
Given two integer arrays `startTime` and `endTime` and given an integer `queryTime`.
The `ith` student started doing their homework at the time `startTime[i]` and finished it at time `endTime[i]`.
Return the number of students doing their homework at time `queryTime`. More formally, return the number of students where `queryTime` lays in the interval `[startTime[i], endTime[i]]` inclusive.
Example 1:
Input: startTime = [1,2,3], endTime = [3,2,7], queryTime = 4
Output:
1
Explanation:
We have 3 students where:
The first student started doing homework at time 1 and finished at time 3 and wasn't doing anything at time 4.
The second student started doing homework at time 2 and finished at time 2 and also wasn't doing anything at time 4.
The third student started doing homework at time 3 and finished at time 7 and was the only student doing homework at time 4.
Example 2:
Input: startTime = , endTime = , queryTime = 4
Output:
1
Explanation:
The only student was doing their homework at the queryTime.
Constraints:
• `startTime.length == endTime.length`
• `1 <= startTime.length <= 100`
• `1 <= startTime[i] <= endTime[i] <= 1000`
• `1 <= queryTime <= 1000`

### 解題

func busyStudent(startTime []int, endTime []int, queryTime int) int {
res := 0
for i := 0; i < len(startTime); i++ {
if queryTime >= startTime[i] && queryTime <= endTime[i] {
res++
}
}
return res
}