1295. Find Numbers with Even Number of Digits

Easy

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

Input: nums = [12,345,2,6,7896]
Output:
 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output:
 1 
Explanation: 
Only 1771 contains an even number of digits.

Constraints:

  • 1 <= nums.length <= 500

  • 1 <= nums[i] <= 105

解題

Runtime: 4 ms, faster than 84.27%

Memory Usage: 3.2 MB, less than 20.98%

func findNumbers(nums []int) int {
    count := 0
    for _, num := range nums {
        if len(strconv.Itoa(num)) % 2 == 0 {
            count++
        }
    }
    
    return count
}

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