1295. Find Numbers with Even Number of Digits
Easy
Given an array
nums of integers, return how many of them contain an even number of digits.Example 1:
Input: nums = [12,345,2,6,7896]
Output:
2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
Example 2:
Input: nums = [555,901,482,1771]
Output:
1
Explanation:
Only 1771 contains an even number of digits.
Constraints:
1 <= nums.length <= 5001 <= nums[i] <= 105
Runtime: 4 ms, faster than 84.27%
Memory Usage: 3.2 MB, less than 20.98%
func findNumbers(nums []int) int {
count := 0
for _, num := range nums {
if len(strconv.Itoa(num)) % 2 == 0 {
count++
}
}
return count
}