# 2133. Check if Every Row and Column Contains All Numbers

Easy
An `n x n` matrix is valid if every row and every column contains all the integers from `1` to `n` (inclusive).
Given an `n x n` integer matrix `matrix`, return `true` if the matrix is valid. Otherwise, return `false`.
Example 1:
Input: matrix = [[1,2,3],[3,1,2],[2,3,1]]
Output:
true
Explanation:
In this case, n = 3, and every row and column contains the numbers 1, 2, and 3.
Hence, we return true.
Example 2:
Input: matrix = [[1,1,1],[1,2,3],[1,2,3]]
Output:
false
Explanation:
In this case, n = 3, but the first row and the first column do not contain the numbers 2 or 3.
Hence, we return false.
Constraints:
• `n == matrix.length == matrix[i].length`
• `1 <= n <= 100`
• `1 <= matrix[i][j] <= n`

### 解題

Runtime: 215 ms, faster than 76.19%
Memory Usage: 7.8 MB, less than 80.95%
func checkValid(matrix [][]int) bool {
length:= len(matrix)
arr := make([]int, length)
for x := 0; x < len(matrix); x++ {
flag := x % 2
for y := 0; y < len(matrix); y++ {
if arr[matrix[x][y]-1] != flag {
return false
}
arr[matrix[x][y]-1] = (x+1) % 2
}
}
arr = make([]int, length)
for y := 0; y < len(matrix); y++ {
flag := y % 2
for x := 0; x < len(matrix); x++ {
if arr[matrix[x][y]-1] != flag {
return false
}
arr[matrix[x][y]-1] = (y+1) % 2
}
}
return true
}