1408. String Matching in an Array

Easy
​
Given an array of string words. Return all strings in words which is substring of another word in any order.
String words[i] is substring of words[j], if can be obtained removing some characters to left and/or right side of words[j].
Example 1:
Input: words = ["mass","as","hero","superhero"]
Output:
["as","hero"]
Explanation:
"as" is substring of "mass" and "hero" is substring of "superhero".
["hero","as"] is also a valid answer.
Example 2:
Input: words = ["leetcode","et","code"]
Output:
["et","code"]
Explanation:
"et", "code" are substring of "leetcode".
Example 3:
Input: words = ["blue","green","bu"]
Output:
[]
Constraints:
  • 1 <= words.length <= 100
  • 1 <= words[i].length <= 30
  • words[i] contains only lowercase English letters.
  • It's guaranteed that words[i] will be unique.
​

解題

Runtime: 3 ms, faster than 81.48%
Memory Usage: 2.4 MB, less than 70.37%
func stringMatching(words []string) []string {
sort.Slice(words, func(i, j int) bool { return len(words[i]) > len(words[j]) })
m := make(map[string]bool)
ans := make([]string, 0)
for i, word := range words {
for j:=i+1; j<len(words); j++ {
if strings.Contains(word, words[j]) {
if !m[words[j]] {
ans = append(ans, words[j])
m[words[j]] = true
}
}
}
}
return ans
}