# 2418. Sort the People

Easy
You are given an array of strings `names`, and an array `heights` that consists of distinct positive integers. Both arrays are of length `n`.
For each index `i`, `names[i]` and `heights[i]` denote the name and height of the `ith` person.
Return `names` sorted in descending order by the people's heights.
Example 1:
Input: names = ["Mary","John","Emma"], heights = [180,165,170]
Output: ["Mary","Emma","John"]
Explanation: Mary is the tallest, followed by Emma and John.
Example 2:
Input: names = ["Alice","Bob","Bob"], heights = [155,185,150]
Output: ["Bob","Alice","Bob"]
Explanation: The first Bob is the tallest, followed by Alice and the second Bob.
Constraints:
• `n == names.length == heights.length`
• `1 <= n <= 10^3`
• `1 <= names[i].length <= 20`
• `1 <= heights[i] <= 10^5`
• `names[i]` consists of lower and upper case English letters.
• All the values of `heights` are distinct.

### 解題

type Person struct {
name string
height int
}
func sortPeople(names []string, heights []int) []string {
arr := make([]Person, 0)
for i, name := range names {
p := Person{name, heights[i]}
arr = append(arr, p)
}
sort.Slice(arr, func(i, j int) bool {
return arr[i].height > arr[j].height
})
ans := make([]string, 0)
for _, n := range arr {
ans = append(ans, n.name)
}
return ans
}